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 Á¶È¸ : 1455 , 2003/12/06 16:19
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Äھ 256ºñÆ®·Î µ¿ÀÛÇϱ¸¿ä. ¸Þ¸ð¸®´Â 2.5ns ¶ó±¸ °¡Á¤Çϱ¸¿ä.
±×·³ ¸Þ¸ð¸®´ë¿ªÆøÀÌ 800Mhz ÀÌÀݾƿä?


204,800Mbit/s ±×·³ ÀÌ·¸°Ô ³ª¿À´Â°Ô ¸ÂÁö¿ä?
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  achtung (ID) / 03-12-06 18:37/ ÀÌ´ñ±Û¿¡´ñ±Û´Þ±â
  Sol> 256bit x 400 MHz x 2 (DDR) = 204,800 Mbit(s)/sec
(8bit = 1byte..so substitute this equation,)
204,800 / 8 = 25,600 Mbyte(s)/sec
(1024MB = 1GB ... substitute!)
25,600 / 1024 = 25 GB/sec

Therefore, 25GB/sec is the bandwidth which we want to know.
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